Question

Use Log(b)2 = 0.401, log(b)3 =0.503, and log(b)5 = 0.842 to approximate the value of the given logarithm to decimal places log(b)50 . Assume that b>0 and
`b\\eq 1`

Answer 1

• ≈ 2.085

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Given

• 
  `log_b2 = 0.401, \ log_b3=0.503, \ log_b5=0.842`

Work out the value of
`log_b50`

• 
  `log_b50=`
• 
  `log_b(2*25)=`
• 
  `log_b(2*5^2)=`
• 
  `log_b2+log_b5^2=`
• 
  `log_b2+2log_b5=`
• 
  `0.401 + 2*(0.842)=`
• 
  `2.085`