Final Answer:
2 sigma bonds. In a molecule with sp3d hybridization and linear molecular geometry, two sigma bonds are formed by the central atom. This hybridization involves one s, three p, and one d orbital, contributing to the formation of two sigma bonds. So, the correct answer is 2) 2 sigma bonds.
Step-by-step explanation:
Hybridization: The sp3d hybridization implies the involvement of one s, three p, and one d orbitals, creating five hybrid orbitals in total.
Linear Molecular Geometry: In a molecule with linear geometry, there are two possibilities: either no lone pairs on the central atom or two identical atoms bonded to the central atom. In both cases, the molecular geometry remains linear.
Sigma Bonds: Each sigma bond involves the overlap of two orbitals. In a linear molecule with no lone pairs on the central atom, there are two sigma bonds formed by the central atom.
Therefore, So, the correct answer is 2) 2 Sigma Bonds.