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Consider the paraboloid and the point on the level curve. Compute the slope of the line tangent to the level curve at p and verify that the tangent line is orthogonal to the gradient at that point.

User Sean Reid
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Final Answer:

The slope of the tangent line to the level curve at point
\( p \) is equal to the negative reciprocal of the gradient of the paraboloid at that point, confirming that the tangent line is orthogonal to the gradient at
\( p \).

Step-by-step explanation:

Consider a paraboloid defined by the equation
\( z = f(x, y) \), and let
\( p = (x_0, y_0, z_0) \) be a point on the level curve of this paraboloid. The gradient of the paraboloid at point
\( p \) is given by the vector
\( \\abla f = ((\partial f)/(\partial x), (\partial f)/(\partial y)) \). The level curve at point
\( p \) is represented by the equation
\( f(x, y) = z_0 \).

To find the slope of the tangent line to the level curve at
\( p \), we can use the fact that the gradient is orthogonal to the level curve. The tangent vector
\( \mathbf{v} \) to the level curve is parallel to the gradient, so
\( \mathbf{v} = \lambda \\abla f \) for some scalar \( \lambda \). The slope of the tangent line is then given by
\( (\Delta y)/(\Delta x) = (\lambda (\partial f)/(\partial y))/(\lambda (\partial f)/(\partial x)) \). Simplifying, we find that the slope is
\( -(\partial f)/(\partial x) / (\partial f)/(\partial y) \).

Now, the negative reciprocal of the gradient vector is \( -1/\lambda \\abla f \), which is equivalent to
\( -(\partial f)/(\partial y) / (\partial f)/(\partial x) \). Comparing this with the slope of the tangent line, we observe that they are equal, confirming that the tangent line is orthogonal to the gradient at point
\( p \). This relationship holds for any point on the level curve of the given paraboloid.

User Feroze
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