Final answer:
The isomers H and I with the molecular formula C8H11N are likely ortho-chloromethylbenzene and para-chloromethylbenzene, respectively, which are positional isomers with different arrangements of chlorine and methyl groups on a benzene ring.
Step-by-step explanation:
To identify the structures of isomers H and I with the molecular formula C8H11N, one must consider the possible arrangements of carbon atoms and the functional group, an amine (NH), in this case. Since the compound must also include a benzene ring, as suggested by the given carbon count, we can deduce that we are dealing with derivatives of ethylbenzene (which has 7 carbons in the ring and one in the ethyl group) with a nitrogen atom substituting one of the hydrogens.
For isomer H, if the molecule has an adjacent chlorine and methyl (CH3) group on the benzene ring, this would represent ortho-chloromethylbenzene. For isomer I, with the chlorine and methyl group separated by two carbons on the benzene ring, this would be para-chloromethylbenzene. These are examples of positional isomers, where the connectivity of atoms differs, leading to distinct physical and chemical properties.
It is important to note that the actual location of the substituents (chlorine and methyl group) on the benzene ring can vary, resulting in multiple possibilities for isomers. However, since the question specifically references two isomers with particular relative positions of substituents, these structures are the likely answers.