Question

What is the behavior of an RL circuit with initial conditions in the Laplace domain?

1) The current in the circuit decays exponentially
2) The voltage across the inductor decays exponentially
3) The voltage across the resistor decays exponentially
4) The current in the circuit increases exponentially

Answer 1

In an RL circuit with initial conditions, the current in the circuit decays exponentially while the voltage across the inductor also decays exponentially as the current approaches its final value.

Step-by-step explanation:

When a series connection of a resistor and an inductor, also known as an RL circuit, is connected to a voltage source, the time variation of the current follows an exponential behavior. The current in the circuit starts from zero and eventually rises to a steady-state value determined by the voltage and the resistance in the circuit. The voltage across the inductor also decays exponentially as the current approaches its final value.