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Write the ion-product expression for chromium(iii) hydroxide?

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Final answer:

The solubility product expression for chromium(III) hydroxide is given by Ksp = [Cr3+][OH-]^3, where Ksp is the solubility product constant and [Cr3+] and [OH-] are the concentrations of chromium(III) and hydroxide ions, respectively.

Step-by-step explanation:

The ion-product expression for chromium(III) hydroxide, Cr(OH)3, involves writing the balanced equation for its dissolution into ions in water and then expressing the product of the concentrations of the resultant ions, each raised to the power of their stoichiometric coefficients from the balanced equation. When chromium(III) hydroxide dissolves in water, it dissociates as follows:

Cr(OH)3(s) ⇌ Cr3+(aq) + 3 OH-(aq)

From this equation, the ion-product expression, also known as the solubility product constant (Ksp), is formed by multiplying the concentration of the chromium(III) ions by the concentration of the hydroxide ions cubed, as there are three hydroxide ions for every one chromium(III) ion produced.

The solubility product expression for chromium(III) hydroxide is:

Ksp = [Cr3+][OH-]3

This expression is essential in calculations involving the solubility and precipitation of chromium(III) hydroxide.

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