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A drag racer starting from rest, travels 6.0 m in 1.0s. Suppose the car continues this acceleration for an additional 4.0s. What is the total distance traveled by the car?

1) 10.0 m
2) 12.0 m
3) 14.0 m
4) 16.0 m

User Meatrobot
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1 Answer

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Final answer:

The total distance traveled by the drag racer, which accelerated from rest, is calculated based on the initial distance traveled in the first second and the acceleration determined from that. The total distance is found by adding the initial distance to the distance traveled during the subsequent 4 seconds, resulting in a total of 102.0 m.

Step-by-step explanation:

The question involves calculating the total distance traveled by a drag racer based on its acceleration and the time taken. Given that the drag racer travels 6.0 m in the first 1.0 s from rest, we can determine its acceleration using the formula d = 0.5 a t^2, where d is the distance traveled, a is the acceleration, and t is the time.

To find the acceleration, we solve for a:

  • a = (2 * d) / t^2
  • a = (2 * 6.0 m) / (1.0 s)^2 = 12.0 m/s^2

Now that we have the acceleration, we can calculate the distance traveled during the next 4.0 s:

  • d = 0.5 * a * t^2 = 0.5 * 12.0 m/s^2 * (4.0 s)^2 = 96.0 m

To find the total distance traveled, we add the distances traveled in the first 1.0 s and the subsequent 4.0 s:

  • Total distance = 6.0 m + 96.0 m = 102.0 m

Therefore, the drag racer will travel a total distance of 102.0 m in 5.0 seconds.

User JeeShen Lee
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