Final answer:
In physics, when an object is in free fall, its final velocity before impacting the water can be calculated using the equation v = g × t. For a time of 2.00 seconds, the final velocity would be 19.6 m/s, so the correct answer is (c) 19.6 m/s.
Step-by-step explanation:
The question relates to the concept of free fall in physics. When a woman jumps off a cliff from a standstill, the speed at which she would be falling right before she hit the water is dependent on the acceleration due to gravity and the time spent in free fall. The formula to calculate the final velocity (v) before impact is given by:
v = g × t
Where g is the acceleration due to gravity (9.80 m/s²) and t is the time spent in free fall. If the student has provided the time t as 2.00 s, we would calculate the velocity as:
v = 9.80 m/s² × 2.00 s = 19.6 m/s
Therefore, the pebble would be going at a velocity of 19.6 m/s when it hits the water. Based on the given options, the correct answer is (c) 19.6 m/s.