Final answer:
To convert 20.07 inches/acre of rainfall to pounds/acre, multiply the inches by the area of an acre in square inches and then multiply by the density of water, which is approximately 0.036 pounds per cubic inch. The resulting weight of rainfall is approximately 4,546,617.38 pounds per acre.
Step-by-step explanation:
To convert 20.07 inches/acre of rainfall to pounds/acre, we need to know the density of water. The density of water is approximately 8.34 pounds per gallon. Since there are 231 cubic inches in a gallon, we can divide 8.34 pounds by 231 cubic inches to find the density of water to be approximately 0.036 pounds per cubic inch.
Now, to convert inches of rainfall to pounds per acre, we need to multiply the inches by the area of an acre in square inches. One acre is equal to 43,560 square feet, which is equal to 6,272,640 square inches. Therefore, 20.07 inches multiplied by 6,272,640 square inches gives us approximately 125,961,676.8 cubic inches of rainfall.
Finally, we can multiply the cubic inches of rainfall by the density of water to find the weight of the rainfall. 125,961,676.8 cubic inches multiplied by 0.036 pounds per cubic inch gives us approximately 4,546,617.38 pounds of rainfall per acre.