Final answer:
Without complete reaction details, we assume a hypothetical double replacement reaction to illustrate the concept. For instance, KOH reacting with HBr would form KBr and H2O. Additionally, rate conversion between reactants and products relies on their stoichiometric relationship in a balanced equation.
Step-by-step explanation:
Prediction of Major Products in a Chemical Reaction
The reaction in question is not clearly defined with the given information 'Br + OK?'. It seems to have a typo or incomplete information. However, based on the context of double replacement reactions provided, let's clarify the concept: when we have a double replacement reaction, the cations and anions in the reacting compounds 'switch partners' to form new ionic compounds.
For example, if we consider a reaction between a bromide salt and potassium hydroxide (KOH), the reaction could resemble something like:
KOH (potassium hydroxide) + HBr (hydrogen bromide) → KBr (potassium bromide) + H2O (water)
In this double replacement reaction, KOH donates a K+ cation to form KBr, and HBr donates a Br- anion to form H2O. These reactions are generally driven by the formation of a precipitate, a gas, or a weakly ionizing compound such as water.
As for the calculation involving the rate of disappearance and appearance of substances, it's based on stoichiometry principles. In the given reaction 5Br- + BrO3- + 6H+ → 3Br2 + 3H2O, the rate of disappearance of Br- ions can be related to the rate of appearance of Br2 molecules by considering their stoichiometric coefficients. Since 5 moles of Br- produce 3 moles of Br2, the appearance rate of Br2 would be 3/5 times the disappearance rate of Br-.