Final answer:
To find the electric field required to generate a 30.0 A current in an aluminum wire, the formula I=σEA where I is the current, E is the electric field, A is the cross-sectional area, and σ is the electrical conductivity is used. However, without the wire's diameter, conductivity value, or additional details, it is not possible to calculate the precise electric field needed.
Step-by-step explanation:
To determine what electric field e' would have been required to create a current of 30.0 A in an aluminum wire, we need to use the relationship between current (I), electric field (E), and conductivity (σ) for a homogeneous material, which is given by I=σEA, where I is the current, E is the electric field, A is the cross-sectional area, and σ is the electrical conductivity of the material.
Assuming the aluminum wire is of the same diameter for which we have the given current, we can calculate E as follows:
E = I/(σA)
The area A can be calculated using the formula for the area of a circle, A = πd²/4, where d is the diameter of the wire.
Unfortunately, without the specific value of the wire diameter, electrical conductivity, or additional information about the conditions under which the wire carries the current, we cannot calculate a precise value for the electric field e'. You would need these values to proceed with a calculation.