Final answer:
The block is completely submerged, so the length of the block above water is 0.0 cm. This is determined by applying Archimedes' principle, which states that the buoyant force equals the weight of the displaced fluid.
Step-by-step explanation:
The question pertains to the concept of buoyancy, which is part of Physics. To find the length of the block above water, we need to apply the principle of Archimedes which states that the upward buoyant force exerted on a body immersed in a fluid is equal to the weight of the fluid that the body displaces. Given the dimensions of the block (2.0 cm × 2.0 cm × 8.0 cm), we must first calculate the volume of the block, and then determine how much of that volume needs to be submerged in water to equal the weight of the block.
Assuming the block is of uniform density and floats without tilting, we can proceed as follows:
- Calculate the volume of the block: Volume = length × width × height = 2.0 cm × 2.0 cm × 8.0 cm = 32.0 cm³.
- Since the block is floating, the weight of the displaced water equals the weight of the block.
- Given the density of water is 1 g/cm³, the block displaces water weighing 32 grams (as the weight of the block must be equal to the weight of the water displaced).
- The volume of water displaced must therefore be 32 cm³, which is the entire volume of the block.
- Since the block is completely submerged, there is no length of the block above water. The length of the block above water is 0.0 cm.