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Find the average value of f(x) = x² - 1/x, 1 ≤ x ≤ 9.

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Final answer:

The average value of the function f(x) = x² - 1/x over the interval [1, 9] is found by integrating the function over the interval and then dividing by the interval's length.

Step-by-step explanation:

To find the average value of the function f(x) = x² - 1/x over the interval [1, 9], we must integrate the function over the interval and then divide by the length of the interval. The average value of a function f(x) from a to b is given by the formula:

Average value = (1 / (b - a)) ∫ f(x) dx

Here, a = 1 and b = 9. We'll perform the following steps to compute the average value:

  1. First, calculate the definite integral of f(x) from 1 to 9.
  2. Then, divide the result by 9 - 1, which is the length of the interval.

By performing the integration, we get the following result:

Integral of f(x) from 1 to 9 = ∫ (x² - 1/x) dx

This integration gives us a value, which we then divide by 8 to get the average value of the function over the given interval.

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