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Suppose the conducting spherical shell carries a charge of ________?

User Shinobii
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1 Answer

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Final answer:

The charge density on the inner surface of the shell is -2.49 × 10^-11 C/m^2, on the outer surface is 3.99 × 10^-11 C/m^2, and the net charge on the conductor is -5.0 × 10^-12 C.

Step-by-step explanation:

The charge density on the inner surface of the shell can be found using the formula:



charge density = charge / surface area



Since the shell is conducting, the charges distribute themselves uniformly on the inner and outer surfaces of the shell. Therefore, the charge on the inner surface of the shell is equal in magnitude and opposite in sign to the charge at the center of the shell. So, the charge density on the inner surface is -5.0 × 10-12 C / (4π(0.035)2 m2) = -2.49 × 10-11 C/m2.



The charge density on the outer surface of the shell is equal in magnitude and sign to the charge at the center of the shell. So, the charge density on the outer surface is 5.0 × 10-12 C / (4π(0.04)2 m2) = 3.99 × 10-11 C/m2.



The net charge on the conductor is equal to the charge at the center of the shell, which is -5.0 × 10-12 C.

User TeamWild
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