Question

A puck of mass m=0.085 kg is moving in a circle on a horizontal frictionless surface. It is held in its path by a massless string of length l=0.24 m. The puck makes one revolution every t=0.45 s. What is the centripetal force acting on the puck?

1) 0.085 N
2) 0.19 N
3) 0.38 N
4) 0.85 N

Answer 1

The centripetal force acting on the puck is approximately 0.38 N.

Step-by-step explanation:

The centripetal force acting on the puck can be calculated using the formula:

Fc = (m * v2) / r

Where:
- Fc is the centripetal force
- m is the mass of the puck
- v is the linear velocity of the puck
- r is the radius of the circular path

Given:
- m = 0.085 kg
- v = 2πr / t (using the formula for linear velocity in terms of the radius and time to complete one revolution)
- r = 0.24 m
- t = 0.45 s

Substituting the given values into the formula:

Fc = (m * ((2πr / t)2)) / r

Calculating:

Fc = (0.085 * ((2π*0.24 / 0.45)2)) / 0.24

Fc ≈ 0.38 N

Hence, the centripetal force acting on the puck is approximately 0.38 N.