Final answer:
A 12kg block released on a frictionless incline will accelerate due to the component of gravitational force acting along the incline, described by the formula mg sin(theta).
Step-by-step explanation:
The question pertains to the physics of mechanics, specifically the dynamics of a block on an inclined surface. A 12 kg block released from rest on a frictionless incline would experience acceleration due to gravity. The component of gravitational force acting along the incline would be mg sin(θ) where m is the mass of the block, g is the acceleration due to gravity, and θ is the angle of the incline with the horizontal. Without friction, there would be no opposing force, and therefore, the acceleration of the block would be g sin(θ).