Final answer:
In the 1H NMR spectrum of CH₃OCH₂CH₂OCH₃, there would be two distinct signals, representing the two unique hydrogen environments: the methoxy (CH₃) groups and the methylene (-CH₂-) groups.
Step-by-step explanation:
The student is asking how many signals they would expect in the 1H NMR spectrum of the compound CH₃OCH₂CH₂OCH₃. To determine the number of signals, we must identify the unique environments of hydrogen atoms in the molecule. In this compound, there are three different environments for hydrogen atoms: the hydrogens on the two methoxy groups (-OCH₃) are equivalent, the hydrogens on the two methylene groups (-CH₂-) are equivalent, and hence we have two different sets of equivalent hydrogens.
Therefore, the 1H NMR spectrum of CH₃OCH₂CH₂OCH₃ would show two distinct signals, one for the methyl group hydrogens and one for the methylene group hydrogens.