Question

Given the following reaction at equilibrium at 300.0 K: NH₄⁺HS (s) ⇌ NH₃ (g) + H₂S (g). If PNH₃ = PH₂S = 0.103 atm, Kp = ________?

Answer 1

The equilibrium constant Kp for the reaction NH4HS(s) ⇌ NH3(g) + H2S(g) at 300.0 K, given that PNH3 = PH2S = 0.103 atm, is calculated to be 0.010609 atm².

Step-by-step explanation:

To determine the value of the equilibrium constant Kp for the reaction NH₄⁺(aq) + HS⁻(s) ⇌ NH₃(g) + H₂S(g), we use the expression for Kp, which is product of the partial pressures of the gaseous products, each raised to the power of its coefficient in the balanced equation. In this case, since the coefficients are both 1, Kp will be the product of the partial pressures of NH₃ and H₂S. Given that PNH₃ = PH₂S = 0.103 atm, we have:

Kp = PNH₃ * PH₂S
= 0.103 atm * 0.103 atm
= 0.010609 atm²