Question

Write the overall molecular equation for the reaction of hydroiodic acid (HI) and potassium hydroxide. Include physical states. Enter the formula for water as H₂O.

Answer 1

The overall molecular equation for the reaction of hydroiodic acid (HI) and potassium hydroxide (KOH) is HI(aq) + KOH(aq) → KI(aq) + H₂O(l), where HI is a strong acid and KOH is a strong base. The net ionic equation for this neutralization reaction is H+(aq) + OH-(aq) → H₂O(l).

Step-by-step explanation:

The overall molecular equation for the reaction between hydroiodic acid (HI) and potassium hydroxide (KOH) is given by the formula:

HI(aq) + KOH(aq) → KI(aq) + H₂O(l)

This is a neutralization reaction where the hydrogen ion (H+) from hydroiodic acid reacts with the hydroxide ion (OH-) from potassium hydroxide to form potassium iodide (KI) and water (H₂O). The reaction involves a strong acid (HI) and a strong base (KOH), both of which dissociate completely in an aqueous solution.

Following the hints provided, to write the net ionic equation for the neutralization of a strong acid with an ionic hydroxide, we use these steps:

1. Identify all strong electrolytes and represent them as ions in the aqueous solution.
2. Write the balanced formula for the molecular equation.
3. Write the ionic equation, showing all aqueous substances as ions.
4. Eliminate the spectator ions to find the net ionic equation.

Considering the above steps, the net ionic equation for this reaction will be:

H+(aq) + OH-(aq) → H₂O(l)