Final answer:
The values of x for which the point (x,y) lies on both the line and the parabola satisfy the quadratic equation y = ax + bx².
Step-by-step explanation:
The values of x for which the point (x,y) lies on both the line and the parabola satisfy the quadratic equation y = ax + bx².
To derive this equation, we need to solve the equation x = Voxt for t, where x is the x-position of the projectile and t is the time. Then we substitute the value of t into the equation for y = Voyt - (1/2)gt², which describes the y-position of the projectile. The resulting equation will have the form y = ax + bx², where a and b are constants.
For example, if we have a line equation y = mx + c and a parabola equation y = ax² + bx + c, the common equation for the x-values of the point (x,y) lying on both the line and the parabola would be y = ax + bx².