Question

A reaction is first order in A. The rate constant of the reaction is 3.45×10-3 s-1. What is the half-life (t1/2) of the reaction?

Answer 1

The half-life (t1/2) of a first-order reaction with a rate constant of 3.45×10-3 s-1 is calculated using the formula t1/2 = 0.693/k, resulting in a half-life of approximately 200.87 seconds.

Step-by-step explanation:

The question asks for the half-life (t1/2) of a reaction that is first order in reactant A with a given rate constant of 3.45×10-3 s-1. The half-life for a first-order reaction is calculated using the formula t1/2 = 0.693/k, where k is the rate constant. To find the half-life for the given reaction:

1. Use the provided rate constant (k = 3.45×10-3 s-1).
2. Substitute this value into the half-life formula: t1/2 = 0.693/3.45×10-3 s-1.
3. Calculate to find the half-life.

By doing this, the half-life (t1/2) of the reaction is found to be:

t1/2 = 0.693 / (3.45×10-3)

t1/2 ≈ 200.87 s