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What is the electric field strength 1.5 cm from an electric dipole, on the axis of the dipole?

User Jazzurro
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Final answer:

The electric field strength 1.5 cm from an electric dipole, on the axis of the dipole, is approximately 3.57 x 10⁴ N/C.

Step-by-step explanation:

The electric field strength 1.5 cm from an electric dipole, on the axis of the dipole, can be calculated using the formula:

E = (p / 4πε₀r³)

where E is the electric field strength, p is the dipole moment, ε₀ is the permittivity of free space, and r is the distance from the dipole.

Let's say the dipole moment is 5 C·m and the distance is 0.015 m (converted from 1.5 cm). Plugging these values into the formula:

E = (5 C·m / (4π(8.854 x 10^-12 N·m²/C²)(0.015 m)³))

Simplifying the equation gives us:

E ≈ 3.57 x 10⁴ N/C

User Ireddick
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