Question

What will be the output of the following code?

def pass_it(x, y): z = y**x return(z) num1 = 3 num2 = 4 answer = pass_it(num1, num2) print(answer)

Answer 1

The code calculates the result of raising one number to the power of another number and returns the result.

Step-by-step explanation:

The code provided defines a function called pass_it(x, y) which takes two parameters, x and y. The function calculates the value of y raised to the power of x and assigns the result to the variable z. The function then returns the value of z.

Later, the code assigns the values 3 to num1 and 4 to num2. It calls the function pass_it() with the parameters num1 and num2, and assigns the result to the variable answer. Finally, it prints the value of answer.

So, when the code runs, it will calculate the value of 4 raised to the power of 3, which is 64. Therefore, the output of the code will be 64.