Final answer:
The question involves drawing the products of SN1 and E1 reactions, which depend on the nature of the substrate, and the reaction conditions. Tertiary substrates favor these reactions, whereas primary and most secondary substrates do not. Relevant factors include substrate structure, solvent properties, and nucleophile strength.
Step-by-step explanation:
Drawing SN1 and E1 Reaction Products
The SN1 (substitution nucleophilic unimolecular) and E1 (elimination unimolecular) reactions are two possible pathways for a reaction that involves a tertiary substrate, such as a tertiary alkyl halide, alcohol or ether. However, primary and most secondary substrates do not typically proceed through these mechanisms due to the stability requirements of the carbocation intermediate formed during the first, rate-determining step of the reactions. To answer the question, one must draw the respective products for the SN1 reaction (where the nucleophile replaces the leaving group) and the E1 reaction (where an elimination occurs, resulting in a double bond).
For the SN1 pathway, the leaving group departs, forming a carbocation intermediate. The nucleophile then attacks this intermediate, leading to the substitution product. In the case of the E1 pathway, the leaving group also departs, but instead of a nucleophile attack, a hydrogen atom is removed from a neighboring carbon, forming a double bond and resulting in an alkene.
Factors like the substrate structure, solvent, and nucleophile strength play pivotal roles in determining whether an SN1 or E1 (or alternatively SN2 and E2) mechanism occurs. These mechanisms are thoroughly understood in terms of their kinetics and substrate preferences, with tertiary substrates favoring SN1/E1 due to steric hindrance that prevents SN2 and the stable carbocation that can form to facilitate E1.
Ball-and-stick models to represent the products and balanced chemical equations with state symbols would complete the required tasks for this question.