Question

A 12.8 μF capacitor is connected through a 0.885 mΩ resistor to a constant potential difference of 60.0 V. What is the time constant of this circuit?

1) 0.010 s
2) 0.012 s
3) 0.014 s
4) 0.016 s

Answer 1

The time constant of the circuit is 0.011 seconds.

Step-by-step explanation:

The time constant of the circuit can be calculated using the equation T = RC, where T is the time constant, R is the resistance, and C is the capacitance. In this case, the given values are R = 0.885 mΩ and C = 12.8 μF. Substituting these values into the equation, we get T = (0.885 x 10^-3 Ω) x (12.8 x 10^-6 F) = 11.328 x 10^-9 s, which is approximately equal to 0.011 s. Therefore, the time constant of the circuit is 0.011 seconds.