Question

Calculate the value of [n2]eq if [h2]eq = 2.0 m, [nh3]eq = 0.5 m, and kc = 2. n2(g) + 3 h2(g) ⇌ 2 nh3(g)?

Answer 1

The equilibrium concentration of N2 is calculated using the provided equilibrium concentrations for H2 and NH3, along with the equilibrium constant, resulting in [N2]eq being 0.015625 M.

Step-by-step explanation:

To calculate the equilibrium concentration of N2 using the equilibrium concentrations of H2 and NH3 and the equilibrium constant (Kc), we use the balanced chemical equation N2(g) + 3H2(g) ⇌ 2NH3(g). Given that [H2]eq = 2.0 M, [NH3]eq = 0.5 M, and Kc = 2, we can set up the equilibrium expression as:

Kc = [NH3]^2 / ([N2][H2]^3)

Plugging in the known values, we get:

2 = (0.5)^2 / ([N2](2.0)^3)

2 = 0.25 / ([N2] × 8)

To find [N2], we rearrange the equation:

[N2] = 0.25 / (2 × 8)

[N2] = 0.25 / 16

[N2] = 0.015625 M

Therefore, the equilibrium concentration of N2 is 0.015625 M.