Question

For the following reaction 2 R (g) ‡„ Q (g), if the equilibrium concentration of R is 0.776 M and that of Q is 1.22 M at 25 °C, what is the value of the equilibrium constant at this temperature?

Answer 1

The equilibrium constant (Kc) for the reaction 2 R (g) ⇌ Q (g) can be calculated using the provided equilibrium concentrations, resulting in a value of approximately 2.03 at 25 °C.

Step-by-step explanation:

For the reaction 2 R (g) ⇌ Q (g), the value of the equilibrium constant (Kc) can be calculated using the equilibrium concentrations of the substances involved at a given temperature.

In this case, the provided equilibrium concentrations are [R] = 0.776 M and [Q] = 1.22 M at 25 °C. The equilibrium constant for the reaction is given by the expression Kc = [Q]x / [R]y, where x and y are the stoichiometric coefficients from the balanced chemical equation, which in this case are x = 1 for Q and y = 2 for R.

Substituting the given values into the equation for Kc, we get:

Kc = (1.22)1 / (0.776)2

Kc = 1.22 / 0.7762

Kc = 1.22 / 0.601

So, the equilibrium constant Kc is approximately 2.03 at 25 °C.