The magnitude of the car's displacement from its starting point is approximately 88.2 km.
To find the magnitude of the car's displacement, we can use the Pythagorean theorem to add up the east and north components of the car's motion. The car initially moves east for 60 km, which represents the east component of its displacement. Then, it moves north by 20 km, which represents the north component.
Finally, it moves in the direction of 37° east of north for 25 km, which can be split into east and north components using trigonometry. Adding up all these components, we can find the magnitude of the car's displacement.
Using the Pythagorean theorem, we have:
Displacement = √(east^2 + north^2)
Calculating the east and north components:
East component = 60 km + 25 km * cos(37°) = 60 km + 19.23 km = 79.23 km
North component = 20 km + 25 km * sin(37°) = 20 km + 15.07 km = 35.07 km
Plugging these values into the displacement equation:
Displacement = √(79.23^2 + 35.07^2) ≈ 88.2 km
Therefore, the magnitude of the car's displacement from its starting point is approximately 88.2 km.
Complete question:
A car is driven east for a distance of 60km than to the north of 20km and in the direction of 37°east of north 25km the magnitude of car displacement from its starting point is __________.