The graph of f(x) is a horizontal line with a y-intercept at 4/3 and zero slope. The graph of g(x) is a straight, non-horizontal line with a slope of 2 and a y-intercept at 1. The difference in slopes makes g(x) a steeper line than f(x).
The graph of f(x)= 1/3x+1 forms a horizontal line, whereas the graph of g(x)= 1/3(6x)+1 constitutes a linear line with a positive incline.
The graph of f(x) remains constant as x varies, while the graph of g(x) displays a consistent increase with a uniform rate as x increases.
The x-values are input into the function machine. The function machine then performs its operations and outputs the y-values. The function within can be any function.
f(x)=x/3+1
Intercept points are (-1/3, 1)
g(x)=6x/3 +1
Intercept points are (-1/2, 1)
Complete ques:
How does the graph of f(x)1÷3 x+1 compare with the graph of g(x)=1÷3(6 x)+1 ?
Compared to the graph of f_1 the graph of g is Choose...
by a scale factor of Choose...