Final answer:
The magnitude of the force on an electron with a charge of 1.60 × 10⁻¹⁹ C in an electric field of 3.00 × 10⁵ N/C is 4.80 × 10⁻¹⁴ N.
Step-by-step explanation:
To find the magnitude of the force on an electron, we can use the equation F = qE, where F is the force, q is the charge of the electron, and E is the electric field. Given the charge of an electron is e = 1.60 × 10⁻¹⁹ C, and recalling from a provided example that an electric force was calculated to be F = (3.20 × 10⁻¹⁹ C)(3.00 × 10⁵ N/C) = 9.60 × 10⁻¹⁴ N, we see that the second charge is twice that of an electron.
Hence, if the field strength in this example remained constant, the force on a single electron would be half of the calculated force, since the electric force is directly proportional to the charge. Thus, the magnitude of the force on an electron would be F = (1.60 × 10⁻¹⁹ C)(3.00 × 10⁵ N/C) = 4.80 × 10⁻¹⁴ N.