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Be sure to answer all parts. Give the IUPAC name for the following compound:

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Final answer:

Compound (a) is 1,1-dibromo-2-methylpropane and compound (b) is 2,2-dimethylpropane. The IUPAC names are determined by identifying the longest carbon chain, numbering the chain to give substituents the lowest numbers, and assembling the name using the substituent names and the parent chain name.

Step-by-step explanation:

The IUPAC name for compound (a) CH3CH₂CBr2CH3 is 1,1-dibromo-2-methylpropane. Here's how to get the name:

  1. Identify the longest carbon chain, which in this case is 4 carbons long (counting the carbon in the functional group).
  2. Number the carbon chain in a way that gives the bromine substituents the lowest possible numbers.
  3. Name the substituents, in this case, we have two bromine groups. Since there are two of them, they are both considered as di-substituents.
  4. Use the numbers and the substituent names to assemble the IUPAC name, in this case, 1,1-dibromo.
  5. Finally, add the name of the parent chain, which is propane, and the position of the substituents, which is 2-methyl.

The IUPAC name for compound (b) (CH3)3CC1 is 2,2-dimethylpropane. Here's how to get the name:

  1. Identify the longest carbon chain, which in this case is 3 carbons long (counting the carbon in the functional group).
  2. Name the substituents, in this case, we have three methyl groups. Since there are three of them, they are all considered as tri-substituents.
  3. Use the substituent names to assemble the IUPAC name, in this case, 2,2-dimethyl.
  4. Finally, add the name of the parent chain, which is propane.

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