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What is the temperature (in K) of 0.660 mole of neon in a 2.00 L vessel at 4.68 atm?

User ENepper
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1 Answer

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\\ \sf\longmapsto PV=nRT


\\ \sf\longmapsto 4.67(2)=0.66(8.314)T


\\ \sf\longmapsto 9.34=5.48T


\\ \sf\longmapsto T=1.7°C

  • T=274.7k

Key words

  • P=Pressure
  • V=Volume
  • n=No of moles
  • R=Universal gas constant
  • T=Temperature
User Alex Pakka
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