Question

For the reaction Mn(s) + O₂(g) → MnO₂(s), compute the theoretical yield of product (in moles) for each of the following initial amounts of reactants?

Answer 1

Theoretical yield of product in moles can be determined using the balanced chemical equation and the molar ratios of the reactants and products.

Step-by-step explanation:

The theoretical yield of product in moles can be determined using the balanced chemical equation and the molar ratios of the reactants and products. In this reaction, Mn(s) reacts with O₂(g) to produce MnO₂(s). The balanced equation shows that the ratio of Mn to MnO₂ is 1:1. Therefore, the moles of MnO₂ produced will be equal to the moles of Mn reacted.

If the initial amount of Mn is given, then the theoretical yield of MnO₂ can be calculated by converting the mass of Mn to moles using its molar mass, and then using the molar ratio to determine the moles of MnO₂.

For example, if the initial amount of Mn is 2.0 moles, then the theoretical yield of MnO₂ will also be 2.0 moles.