Final answer:
To draw the structures for the given compounds, follow the rules of organic chemistry nomenclature. For 5-bromo-3-iodoheptanal, start with a heptane chain, locate the bromine at the 5th carbon, iodine at the 3rd carbon, and an aldehyde group at the end. For 5-bromo-4-ethyl-2-heptanone, begin with a heptane chain, add bromine at the 5th carbon, an ethyl group at the 4th carbon, and a ketone group at the 2nd carbon.
Step-by-step explanation:
To draw the structures for the given compounds, we need to follow the rules of organic chemistry nomenclature. Let's take each compound one by one:
a. 5-bromo-3-iodoheptanal: Start by drawing a heptane chain, then locate the bromine at the 5th carbon and the iodine at the 3rd carbon. Attach an aldehyde group at the end of the chain. The final structure should have 7 carbons, with bromine at the 5th carbon, iodine at the 3rd carbon, and an aldehyde group at the end.
b. 5-bromo-4-ethyl-2-heptanone: Begin with a heptane chain, then add a bromine group at the 5th carbon and an ethyl group at the 4th carbon. Place a ketone group at the 2nd carbon. The resulting structure should have 7 carbons, with bromine at the 5th carbon, an ethyl group at the 4th carbon, and a ketone group at the 2nd carbon.