Final answer:
Set B is the only subspace of R⁵ among the given sets.
Step-by-step explanation:
To determine if a set is a subspace of R⁵, it needs to satisfy three conditions:
- The set needs to be closed under vector addition.
- The set needs to be closed under scalar multiplication.
- The set needs to contain the zero vector (0, 0, 0, 0, 0).
Looking at the given sets:
- Set A = {2, 4, 6}, does not satisfy the third condition as it does not contain the zero vector, so it is not a subspace.
- Set B = {14, 16, 18}, satisfies all three conditions and is a subspace of R⁵.
- Set C = {1, 3, 5, 7}, does not satisfy the second condition as it is not closed under scalar multiplication, so it is not a subspace.
- Set D = {0, 12}, does not satisfy the first condition as it is not closed under vector addition, so it is not a subspace.
Therefore, Set B is the only subspace of R⁵ among the given sets.