177k views
1 vote
Find the angle between the intersecting lines x = t, y = 2t, z = -t and x = 1 – t, y = 5t, z = 2t.

User Ravibhagw
by
8.5k points

1 Answer

0 votes

The angle between the lines is approximately 1.75 radians.

The direction vectors of the first line are (1, 2, -1) and the second line are (-1, 5, 2). The angle between two lines is given by:

cos(θ) = (a1 * a2 + b1 * b2 + c1 * c2) / (√(a1^2 + b1^2 + c1^2) * √(a2^2 + b2^2 + c2^2))

Substituting the direction vectors:cos(θ)=


(-1 * 1 + 2 * 5 + (-1) * 2) / (√((1^2 + 2^2 + (-1)^2)) * \sqrt{((-1)^2 + 5^2 + 2^2))

cos(θ) =
6 / √(6) * \sqrt{34

cos(θ) =
\sqrt{6 / 19

θ =
cos^-1(√(6) / 19)

Therefore, the angle between the intersecting lines is approximately 1.75 radians.

User Creuzerm
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.