Final answer:
The balanced chemical equation is: H₂SO₄(aq) + Pb(OH)=(s) – 4Pb(SO.)₂(s) + 4H₂O(l)
Explanation:
The given chemical equation is not balanced.
Let's balance it step by step:
1) Start by counting the number of each type of atom on both sides of the equation.
On the left side:
On the right side:
- - Pb: 1
- - S: 1
- - O: 4
- - H: 2
2) Balance the atoms one by one, starting with the most complex molecule. In this case, let's start with sulfur (S).
On the left side, there is 1 sulfur (S). To balance it, we need 1 sulfur (S) on the right side as well. Add a coefficient of 1 in front of Pb(SO.)>.
H₂SO₄(aq) + Pb(OH)=(s) – Pb(SO.)₂(s) + H₂O(l)
3) Now, let's balance the hydrogen (H) atoms.
On the left side, there are 2 hydrogen (H) atoms. To balance it, we need 4 hydrogen (H) atoms on the right side. Add a coefficient of 4 in front of H₂O.
H₂SO₄(aq) + Pb(OH)=(s) – Pb(SO.)₂(s) + 4H₂O(l)
4) Finally, let's balance the oxygen (O) atoms.
On the left side, there are 4 oxygen (O) atoms. To balance it, we need 4 oxygen (O) atoms on the right side. Add a coefficient of 4 in front of Pb(SO.)₂.
H₂SO₄(aq) + Pb(OH)=(s) – 4Pb(SO.)₂(s) + 4H₂O(l)
Now the equation is balanced with the same number of atoms on both sides. The balanced equation is:
H₂SO₄(aq) + Pb(OH)=(s) – 4Pb(SO.)₂(s) + 4H₂O(l)
Your question is incomplete, but most probably the full question was:
Balance the following chemical equation (if necessary):
H₂SO₄(aq) + Pb(OH)=(s) – Pb(SO.)>(s) + H₂0(l)