Question

Blocks with masses of 1.0 kg, 2.0 kg, and 4.0 kg are lined up in a row on a frictionless table. All three are pushed forward by a 14 N force applied to the 1.0 kg block. What is the acceleration of the system?

1) 2.0 m/s²
2) 4.0 m/s²
3) 6.0 m/s²
4) 8.0 m/s²

Answer 1

The acceleration of the 7.0 kg system pushed by a 14 N force is 2.0 m/s², calculated using Newton's Second Law of Motion.

Step-by-step explanation:

To determine the acceleration of the system consisting of blocks with masses of 1.0 kg, 2.0 kg, and 4.0 kg on a frictionless table being pushed by a 14 N force, we can use Newton's Second Law of Motion. This law states that the acceleration of an object is equal to the net force acting on it divided by its mass (F = ma).

The total mass of the system is the sum of the individual masses:

• mtotal = 1.0 kg + 2.0 kg + 4.0 kg = 7.0 kg

The force applied to move the system is 14 N. Using Newton's Second Law, the acceleration (a) can be calculated as:

a = F / mtotal

a = 14 N / 7.0 kg = 2.0 m/s2

Therefore, the acceleration of the system is 2.0 m/s2.