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1 vote
1 vote

\begin{bmatrix}\sf x+y=7\\ \sf x+2y=11\end{bmatrix}

User Teerapap
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2 Answers

23 votes
23 votes
Possibilities of
x + y
1+ 6
2+5
3+4

x +2y
3+ (2x4)
3+8
=11

x=3
y=4
User Bradley D
by
3.2k points
19 votes
19 votes

Answer:

  • x = 3
  • y = 4

Explanation:

The equations are,

→ x + y = 7

→ x + 2y = 11

Forming the equation for y,

→ x + 2y = 11

→ 2y = 11 - x

→ y = (11 - x)/2

Now the value of x will be,

→ x + y = 7

→ x + (11 - x)/2 = 7

→ (2x + 11 - x)/2 = 7

→ x + 11 = 7 × 2

→ x = 14 - 11

→ [ x = 3 ]

Then the value of y will be,

→ y = (11 - x)/2

→ y = (11 - 3)/2

→ y = 8/2

→ [ y = 4 ]

Hence, the value of y is 4.

User OOM
by
3.1k points