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What are the exact solutions of x2 − 5x − 1 = 0 using x equals negative b plus or minus the square root of the quantity b squared minus 4 times a times c all over 2 times a? (1 point) x = the quantity of 5 plus or minus the square root of 29 all over 2 x = the quantity of negative 5 plus or minus the square root of 29 all over 2 x = the quantity of 5 plus or minus the square root of 21 all over 2 x = the quantity of negative 5 plus or minus the square root of 21 all over 2

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Answer:


x=(5\pm√(29) )/(2)

Explanation:

for the general quadratic equation


ax^2+bx+c=0

we use the following formula to find its solution:


x=(-b\pm√(b^2-4ac) )/(2a)

in our case we would have a=1, b=-5, c=-1, so:


x=(-(-5)\pm√((-5)^2-4(1)(-1)) )/(2(1))=(5\pm√(25+4) )/(2)=(5\pm√(29) )/(2)

User Bart Pelle
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