96.7k views
4 votes
If the supply AC is 10 V the frequency 1 kHz and capacitance 2 µF. What value of 'R' in the circuit would allow a current of 0.1 A to flow? ​

1 Answer

3 votes

Final answer:

In an RLC series circuit, the resistance 'R' can be calculated using Ohm's Law by dividing the voltage 'V' by the current 'I'. In this case, a resistance of 100 ohms would allow a current of 0.1 A to flow in the circuit.

Step-by-step explanation:

In an RLC series circuit, the current flowing through the circuit can be calculated using Ohm's Law, which states that V = IR, where V is the voltage across the circuit, I is the current flowing through the circuit, and R is the resistance. Rearranging the equation to solve for R, we get R = V / I.

In this case, the supply voltage AC is 10 V and the current is 0.1 A. So, substituting these values into the equation, we get R = 10 V / 0.1 A = 100 ohms. Therefore, a resistance of 100 ohms would allow a current of 0.1 A to flow in the circuit.

User Stojevskimilan
by
8.2k points