Answer:
20 m/s, vector quantity & 49s
Step-by-step explanation:
Using the third equation of motion
a = g [gravity] = ~9.8 m/s^2 or 49/5 m/s^2
- v^2 = u^2 + 2gs
- v^2 = 20^2 + 2(9.8)(0)... 0 because the object has landed onto the ground, so S (displacement) = 0
- v^2 = 400
- v = √400
- v = 20
- 20 m/s [vector quantity - goes in a rectilinear motion with a certain direction at certain time intervals]
TO FIND TOTAL AIR TIME:
- v = u + at
- 20 = 20 + 49/5 x t
- 20 = (20 + 49)/5t
- 20 = (100+49t)/5
- t = (20x5)/(1x100x49)
- t = 49
- 49s