Final answer:
6-bit integers are numbers represented using 6 bits and the sum of two such integers is computed like any other numbers. The provided reference material does not align with the original question on computing 6-bit integer sums, so an explanation of addition within the 6-bit limit was provided instead.
Step-by-step explanation:
The original question about computing the sum of 6-bit integers seems to be mismatched with the provided reference material. The reference discusses data values, outcomes with dice and coins, and expected frequencies, all of which do not directly relate to the computation of 6-bit integer sums. However, if we are to discuss 6-bit integers, a 6-bit integer is a number represented using 6 bits, capable of representing 2^6 (64) different values, ranging from 0 to 63 in binary notation.
To compute the sum of two 6-bit integers, you would simply add them together like any other whole numbers, making sure not to exceed the maximum value a 6-bit number can represent. If the sum exceeds 63, this would cause an overflow in a strict 6-bit system. In practice, this is not accounted for in most calculation scenarios as modern computing systems use larger bit widths for integer representations. However, understanding bit limitations is crucial in fields like computer science and digital electronics, where precise control over data sizes is required. For example, summing two values such as 001101 (13 in decimal) and 011010 (26 in decimal) would yield 100111 which is 39 in decimal, well within the 6-bit integer range.