Final answer:
The skeletal structures of 5-bromo-3-iodoheptanal and 5-bromo-4-ethyl-2-heptanone can be drawn using skeletal structure representation.
Step-by-step explanation:
For compound a, 5-bromo-3-iodoheptanal, we can start by drawing the skeletal structure. The aldehyde group is located at the end of the carbon chain, and the bromine and iodine substituents are attached to carbon atoms along the chain. The skeletal structure can be represented as follows:
CH3CH2CH2CH2CH(Br)CH(I)CHO
For compound b, 5-bromo-4-ethyl-2-heptanone, we also start with the skeletal structure. The ketone group is located in the middle of the carbon chain, and the bromine and ethyl substituents are attached to carbon atoms along the chain. The skeletal structure can be represented as follows:
CH3CH2CH2CH2C(Br)(C2H5)COCH2CH3