Question

Use the reactions below and their equilibrium constants to predict the equilibrium constant for the reaction 2a(s)⇌3d(g).

Answer 1

The equilibrium constant Ke for the reaction 2SO₂(g) + O₂(g) = 2SO3(g) at the given equilibrium concentrations is approximately 4.27.

Step-by-step explanation:

To find the equilibrium constant (Ke) for the reaction 2SO₂(g) + O₂(g) = 2SO3 (g) where the concentrations at equilibrium are [SO₂] = 0.90 M, [O₂] = 0.35 M, and [SO3] = 1.1 M, we use the expression for the equilibrium constant in terms of the concentration of the gases. The equilibrium constant expression, Ke, is given by:

Ke = ([SO3]^2) / ([SO₂]^2 × [O₂])

Plugging in the equilibrium concentrations:

Ke = (1.1^2) / (0.90^2 × 0.35)

Ke = 1.21 / (0.81 × 0.35)

Ke = 1.21 / 0.2835

Ke = 4.27 (approx)

Thus, the value of Ke for this reaction at the given concentrations is approximately 4.27.