Question

Triangle inequality proof
/a + b/ ≤ /a/ + /b/

Answer 1

a^2+b^2+2|a||b|≥a2+b2+2ab(|a|+|b|)2≥|a+b|2(∵∀x∈R;x2=|x|2)∴|a|+|b|≥|a+b|\

Explanation: