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If there is anyone that knows this, be very appreciated. Thanks

If there is anyone that knows this, be very appreciated. Thanks-example-1
User Lachlan
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the area of the sector with
\( \theta = (\pi)/(9) \) radians and
\( r = 2 \) is \( (2\pi)/(9) \) square units.

The formula for the area (A) of a sector of a circle is given by:


\[ A = (1)/(2)r^2\theta \]

where:

- r is the radius of the circle,

-
\( \theta \) is the central angle of the sector in radians.

Given r = 2 and
\( \theta = (\pi)/(9) \), substitute these values into the formula:


\[ A = (1)/(2) \cdot (2)^2 \cdot (\pi)/(9) \]

Simplify:


\[ A = (1)/(2) \cdot 4 \cdot (\pi)/(9) \]


\[ A = (2\pi)/(9) \]

So, the area of the sector with
\( \theta = (\pi)/(9) \) radians and r = 2 is
\( (2\pi)/(9) \) square units.

User Gnr
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