Question

If there is anyone that knows this, be very appreciated. Thanks

Answer 1

the area of the sector with
`\( \theta = (\pi)/(9) \)` radians and
`\( r = 2 \) is \( (2\pi)/(9) \)` square units.

The formula for the area (A) of a sector of a circle is given by:

`\[ A = (1)/(2)r^2\theta \]`

where:

- r is the radius of the circle,

-
`\( \theta \)` is the central angle of the sector in radians.

Given r = 2 and
`\( \theta = (\pi)/(9) \)`, substitute these values into the formula:

`\[ A = (1)/(2) \cdot (2)^2 \cdot (\pi)/(9) \]`

Simplify:

`\[ A = (1)/(2) \cdot 4 \cdot (\pi)/(9) \]`

`\[ A = (2\pi)/(9) \]`

So, the area of the sector with
`\( \theta = (\pi)/(9) \)` radians and r = 2 is
`\( (2\pi)/(9) \)` square units.