Question

Ticket at a school play cost four dollars in advance or five dollars at the door. Total ticket sales for an evening production were $448. If no tickets were sold in advance, write and solve a linear equation to find the how many were sold at the door

Answer 1

Let's denote the number of tickets sold at the door as

�

x. Since no tickets were sold in advance, the total revenue is given by the number of tickets at the door multiplied by the door price.

The equation representing the total revenue is

5

�

5x, and it is given that the total ticket sales were $448. Therefore, we can set up the equation:

5

�

=

448

5x=448

Now, solve for

�

x:

�

=

448

5

x=

5

448

�

=

89.6

x=89.6

However, since the number of tickets must be a whole number, we round down to the nearest whole number (as you can't sell a fraction of a ticket). Therefore, approximately 89 tickets were sold at the door.