Question

2sin 2A - sin 4A
2sin 2A + sin 4A
= tan²A​

Answer 1

tan²A - sin²A = tan² A sin²A

from LHS,

tan²A -sin²A

= (sin²A / cos²A) - sin²A……[tan A=sin A/cos A]

= (sin²A - sin²Acos²A) / cos²A

= sin²A (1- cos²A) / cos² A [tan A = sinA / cos A]

= tan²A sin²A= RHS

.•. hence proved

Explanation:

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