Question

Carbon monoxide, CO , and hydrogen react according to the equation below. 2 CO ( g ) + 5 H 2 ( g ) ⟶ C 2 H 6 ( g ) + 2 H 2 O ( g ) What is the maximum volume of C 2 H 6 that can be obtained from 2 6 . 0 L CO ( g ) and 3 9 . 0 L H 2 ( g ) ? Assume that all volumes are measured at the same temperature and pressure. Enter a value accurate to three significant figures.

Answer 1

The maximum volume of C2H6 that can be obtained from 26.0 L of CO and 39.0 L of H2 is 7.80 L. This calculation is based on the limiting reactant, which in this case is hydrogen (H2), as per the stoichiometry of the balanced chemical equation.

Step-by-step explanation:

To determine the maximum volume of C2H6 that can be obtained from the reaction between carbon monoxide (CO) and hydrogen (H2), we apply the concepts of stoichiometry and the assumption that gases behave ideally, meaning equal volumes of gases contain the same number of particles under the same temperature and pressure according to Avogadro's Law.

The balanced chemical equation is 2 CO (g) + 5 H2 (g) → C2H6 (g) + 2 H2O (g).

From this, we can see that 2 volumes of CO react with 5 volumes of H2 to form 1 volume of C2H6.

Given 26.0 L of CO and 39.0 L of H2, we must first identify the limiting reactant.

CO would require (5/2)×26.0 L = 65.0 L of H2 for complete reaction

but only 39.0 L is available, indicating H2 is the limiting reactant.

Then, for every 5 L of H2, 1 L of C2H6 is produced.

Therefore, (1/5)×39.0 L = 7.80 L of C2H6 can be obtained.

This is the maximum volume of C2H6 that can be produced under these conditions.